\ H =\left( \begin{array}{ccccc}
0 & 1 & 0 & 0 & 1 \\
0 & 0 & 1 & 0 & 1 \\
1 & 0 & 0 & 1 & 1 \end{array} \right)\]      \rightarrow \ H' =\left( \begin{array}{ccccc}
1 & 0 & 0 & 1 & 1 \\
0 & 1 & 0 & 0 & 1 \\
0 & 0 & 1 & 0 & 1 \end{array} \right)\] 


\vspace{10 mm}

\ (I_3,A) =\left( \begin{array}{cccccc}
1 & 0 & 0 & |& 1 & 1 \\
0 & 1 & 0 & |& 0 & 1 \\
0 & 0 & 1 & |& 0 & 1 \end{array} \right)\]

\vspace{10 mm}

\ A =\left( \begin{array}{cc}
1 & 1  \\
0 & 1 \\
0 & 1  \end{array} \right)\]

\vspace{10 mm}

\ (-A^{T},I_2) =\left( \begin{array}{cccccc}
 1&1 &1& |& 1 & 0 \\
 0&0 &1 &|& 0 & 1 \end{array} \right)\]

\vspace{10 mm}

\ G =\left( \begin{array}{cccccc}
 1&1 &1&  1 & 0 \\
 0&0 &1& 0 & 1 \end{array} \right)\]

\vspace{10 mm}

Dobijem (5,2)-Linearni kod (n=5 i k=2, zbog G matrice), i broj kodova C, q^{k}=2^{2}=4 .



\begin{center} C=\{ 00000, 11110, 00101, 11011 \} \end{center}