\frac{1}{\sqrt{1-\frac{(\sqrt{3}x)^2}{2}}}=\frac{1}{\sqrt{1-\frac{(\sqrt{3}x)^2}{(\sqrt{2})^2}}}=\frac{1}{\sqrt{1-\bigg( \frac{\sqrt{3}x}{\sqrt{2}}\Bigg )^2}}