\frac{\frac{sin\frac{\pi}{4}cosax+cos\frac{\pi}{4}sinax}{cos\frac{\pi}{4}cosax-sin\frac{\pi}{4}sinax}-1}{sinbx}=\frac{\frac{ax\sqrt{2}}{\frac{\sqrt{2}}{2}a(1-x)}}{sinbx}=\frac{\frac{2ax}{a}}{bx}